Sep 25, 2020 · To calculate the second derivative of a function, you just differentiate the first derivative. From above, we found that the first derivative of cos^2x = -sin (2x). So to find the second derivative of cos^2x, we just need to differentiate -sin (2x) We can use the chain rule to find the derivative of -sin (2x).
23.09.2019 · This video works through the Derivative of cos^2(8x). This includes a Trig Function and Chain Rule. This type of derivative would typically be found in a C...
Find the Derivative - d/dx y=cos(2x). y=cos(2x) y = cos ( 2 x ). Differentiate using the chain rule, which states that ddx[f(g(x))] d d x [ f ( g ( x ) ...
Sep 15, 2015 · First of all y=cos^2x=(cosx)^2 Hence y'=2cosx*(cosx)'=2cosx*(-sinx)=-2cosx*sinx=-sin2x Another way is y=cos^2x=1/2(1+cos2x) Hence y'=1/2*(-sin2x *(2x)')=-sin2x
Jul 04, 2018 · Here, y = cos2(2x) Let , y = u2,where,u = cos2x. ⇒ dy du = 2u and du dx = − sin2x d dx (2x) = − 2sin(2x) Using Chain Rule: dy dx = dy du ⋅ du dx. ⇒ dy dx = 2u ⋅ ( −2sin(2x)) Subst. back , u = cos2x. dy dx = 2cos2x( − 2sin2x)
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14.09.2015 · How do find the derivative of # y = cos^2(x)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Konstantinos Michailidis Sep 15, 2015 First of all #y=cos^2x=(cosx)^2# Hence. #y'=2cosx*(cosx)'=2cosx*(-sinx)=-2cosx*sinx=-sin2x# Another way ...